Problem: If log2(log3(log4x))=log3(log4(log2y))=log4(log2(log3z))=0, then the sum x+y+z is equal to
Answer Choices:
A. 50
B. 58
C. 89
D. 111
E. 1296
Solution:
Since the antilog of 0 is 1 regardless of base, log3(log4x)=log4(log2y)= log2(log3z)=1 and hence log4x=3,log2y=4 and log3z=2.∴x+y+z=43+24 +32=89.