Problem: If a,b, and c are in geometric progression (G.P.) with 0<a<b<c and n>1 is an integer, then logaβn,logbβn,logcβn form a sequence
Answer Choices:
A. which is a G.P.
B. which is an arithmetic progression (A.P.)
C. in which the reciprocals of the terms form an A.P.
D. in which the second and third terms are the nth powers of the first and second respectively
E. None of these
Solution:
Let r>1 denote the ratio of the G.P. a,b,c; so that b=ar and c=ar2 and logb=loga+logr,logc=loga+2logr. Now
logaβn=logn(loga1β),logbβn=logn(logb1β)=logn(loga+logr1β)
and
logcβn=logn(logc1β)=logn((loga+2logr)1β)
have reciprocale which form an A.P. as required.