Problem: Lines L1β,L2ββ¦,L100β are distinct. All lines L4nβ,n a positive integer, are parallel to each other. All lines L4nβ3β,n a positive integer, pass through a given point A. The maximum number of points of intersection of pairs of lines from the complete set {L1β,L2β,β¦,L100β} is
Answer Choices:
A. 4350
B. 4351
C. 4900
D. 4901
E. 9851
Solution:
One hundred lines intersect at most at C2100β=2100(99)β=4950 points. But lines L4β,L8β,β¦,L100β are parallel; hence C225β=300 intersections are lost. Also, lines L1β,L5β,β¦,L97β intersect only at point A, so that C225ββ1=299 more intersections are lost. The maximum number of points of intersection is 4950β300β299=4351.