Problem: If i2=β1, then the sum cos45β+icos135β+β¦+incos(45+90n)β+ β¦+i40cos3645β equals
Answer Choices:
A. 22ββ
B. β10i2β
C. 2212ββ
D. 22ββ(21β20i)
E. 22ββ(21+20i)
Solution:
Since
incos(45+90n)β=β©βͺβͺβ¨βͺβͺβ§β22ββ,n even 2βi2ββ,n odd β
the sum is 22ββ(21β20i).