Problem: If xξ =y and the sequences x,a1β,a2β,y and x,b1β,b2β,b3β,y each are in arithmetic progression, then (a2ββa1β)/(b2ββb1β) equals
Answer Choices:
A. 32β
B. 43β
C. 1
D. 34β
E. 23β
Solution:
b2ββb1βa2ββa1ββ=(yβx)/4(yβx)/3β=34β.