Problem: Find a positive integral solution to the equation
2+4+6+β―+2n1+3+5+β―+(2nβ1)β=116115β.
Answer Choices:
A. 110
B. 115
C. 116
D. 231
E. The equation has no positive integral solutions.
Solution:
Sumbing the arithmetic progressions yields
116115β=2+4+β―+2n1+3+β―+(2nβ1)β=n(n+1)n2β;116115β=n+1nβ;n=115.