Problem: In the adjoining figure, CD is the diameter of a semi-circle with center O. Point A lies on the extension of DC past C; point E lies on the semi-circle, and B is the point of intersection (distinct from E ) of line segment AI : with the semi-circle. If length AB equals length OD, and the measure of β EOD is 45β, then the measure of β BAO is
Answer Choices:
A. 10β
B. 15β
C. 20β
D. 25β
E. 30β
Solution:
Draw line segment BO, and let x and y denote the ineasures of β EOD and β BAO, respectively. Observe that AB=OD=OE=OA, and apply the theorem on exlerior angles of triangles to β³ABO and β³AEO to obtain β EBO=β BEO=2y and
x=3y.
Thus 45β=3y
15β=y
OR
Since the measure of an angle formed by two secants is half the difference of the intercepled arcs.
y=21β(xβy),y=3xβ=345ββ=15β.