Problem: A circle with area A1β is contained in the interior of a larger circle with area A1β+A2β. If the radius of the larger circle is 3 , and if A1β,A2β,A1β+A2β is an arithmetic progression, then the radius of the smaller circle is
Answer Choices:
A. 23ββ
B. 1
C. 3β2β
D. 23β
E. 3β
Solution:
Since A1β,A2β,A1β+A2β are in arithmetic progression,