Problem: Find the sum of the squares of all real numbers satisfying the equation
x256β25632=0
Answer Choices:
A. 8
B. 128
C. 512
D. 65536
E. 2(25632)
Solution:
Since
βx256β25632=x(28)β(28)32=x(28)β2(28)=(x(27)+2(27))(x(26)+2(26))β―(x+2)(xβ2)β
the sum of the squares of the real roots is 8.