Problem:
If AB and CD are perpendicular diameters of circle Q, and β QPC=60β, then the length of PQ divided by the length of AQ is
Answer Choices:
A. 23ββ
B. 33ββ
C. 22ββ
D. 21β
E. 32β
Solution:
Triangle PQC is a 30ββ60ββ90β right triangle. Since AQ=CQ
AQPQβ=CQPQβ=3β1β=33ββ.