Problem: When the polynomial x3β2x^{3}-2x3β2 is divided by the polynomial x2β2x^{2}-2x2β2, the remainder is
Answer Choices:
A. 222
B. β2-2β2
C. β2xβ2-2x-2β2xβ2
D. 2x+22x+22x+2
E. 2xβ22x-22xβ2
Solution:
xx2+0xβ2x3+0x2+0xβ2x3+0x2β2x2xβ2=(remainder)\begin{array}{r|rrrl} & x & & & \\ \hline x^2 + 0x - 2 & x^3 & + 0x^2 & + 0x & - 2 \\ & x^3 & + 0x^2 & - 2x & \\ \hline & & & 2x & -2 = \text{(remainder)} \end{array} x2+0xβ2βxx3x3β+0x2+0x2β+0xβ2x2xββ2β2=(remainder)ββ