Problem:
The area of the figure where sides AF and CD are parallel, as are sides AB and FE, and sides BC and ED, each side has length 1, and β FAB=β BCD=60β is
Answer Choices:
A. 23ββ
B. 1
C. 23β
D. 3β
E. 2
Solution:
Draw in lines BF,BE and BD. There are now 4 equilateral triangles with side length 1. (For instance, β³FAB is equilateral because AF=AB=1 and β A=60β.)