One should verify that x1β,x2β and x3β are not integers. Here is a sketch of one way to do this. First, prove by induction that the sequence {xnβ} is increasing. Next, since 1<x1β<2 and x4β=3, it suffices to show that neither x2β nor x3β is 2. As for x2β, note that x1β<3/2 (since x1β3=3<27/8 ). Thus
x2β=x1x1ββ<(3/2)3/2=27/8β<2
To show x3β>2, show that x1β>2β and do a similar manipulation.
Note. x2β and x3β are integers raised to radicals, e.g.,
x2β=3(31/9β)
There is a general theorem which says (as a special case) that such numbers cannot be integers (except when the base is 0 or 1), but the proof is very deep.