Problem:
Which terms must be removed from the sum
21β+41β+61β+81β+101β+121β
if the sum of the remaining terms is to equal 1?
Answer Choices:
A. 41β and 81β
B. 41β and 121β
C. 81β and 121β
D. 61β and 101β
E. 81β and 101β
Solution:
21β+41ββ+61β+81β+101β+121β=12060β+12030β+12020β+12015β+12012β+12010ββ
Since 60+30+20+10=120, it is clear that one may remove 12015β=81β and 12012β=101β. Furthermore, one sees easily from the right hand side above that no other terms sum to 12027β. Thus one must remove 81β and 101β.