Problem:
In the figure, β³ABC has a right angle at C and LA=20β. If BD is the bisector of β ABC, then β BDC=
Answer Choices:
A. 40β
B. 45β
C. 50β
D. 55β
E. 60β
Solution:
Since β C=90β and β A=20β, we have β ABC=70β. Thus β DBC=35β. It follows that β BDC=90ββ35β=55β.