Problem:
Suppose that p and q are positive numbers for which
log9β(p)=log12β(q)=log16β(p+q)
What is the value of q/p?
Answer Choices:
A. 34β
B. 21β(1+3β)
C. 58β
D. 21β(1+5β)
E. 916β
Solution:
Let t be the common value of log9β(p),log12β(q) and log16β(p+q). Then
p=9t,q=12t, and 16t=p+q=9t+12t
Divide the last equation by 9t and note that
9t16tβ=(3t4tβ)2=(9t12tβ)2=(pqβ)2
Now let x stand for the unknown ratio q/p. From the division referred to above we obtain x2=1+x, which leads easily to x=21β(1+5β) since x must be the positive root.