Problem: The slope of the line x3+y2=1\dfrac{x}{3}+\dfrac{y}{2}=13xβ+2yβ=1 is
Answer Choices:
A. β32-\dfrac{3}{2}β23β
B. β23-\dfrac{2}{3}β32β
C. 13\dfrac{1}{3}31β
D. 23\dfrac{2}{3}32β
E. 32\dfrac{3}{2}23β
Solution:
Rewrite the equation as y=β23x+2y=-\dfrac{2}{3} x+2y=β32βx+2. With the equation in this form, the slope is the coefficient of xxx.