Problem: (β1)52+125=(-1)^{5^{2}}+1^{2^{5}}=(β1)52+125=
Answer Choices:
A. β7\mathbf{- 7}β7
B. β2-2β2
C. 000
D. 111
E. 575757
Solution:
(β1)52+125=(β1)25+132=β1+1=0(-1)^{5^{2}}+1^{2^{5}}=(-1)^{25}+1^{32}=-1+1=0(β1)52+125=(β1)25+132=β1+1=0.