Note that x+x2+1β1ββ xβx2+1βxβx2+1ββ=1x2+1ββxβ. Hence
x+x2+1ββx+x2+1β1β=2x,
which is rational if and only if x is rational. To show that this is the only answer, show that each of the other sets is different from the set of rational numbers.