Problem: 19+116=\sqrt{\dfrac{1}{9}+\dfrac{1}{16}}=91β+161ββ=
Answer Choices:
A. 15\dfrac{1}{5}51β
B. 14\dfrac{1}{4}41β
C. 27\dfrac{2}{7}72β
D. 512\dfrac{5}{12}125β
E. 712\dfrac{7}{12}127β
Solution:
19+116=16+9144=512\sqrt{\dfrac{1}{9}+\dfrac{1}{16}}=\sqrt{\dfrac{16+9}{144}}=\dfrac{5}{12}91β+161ββ=14416+9ββ=125β.