Problem:
Let x be a real number selected uniformly at random between 100 and 200. If ⌊x⌋=12, find the probability that ⌊100x⌋=120. (⌊v⌋ means the greatest integer less than or equal to v.)
Thus, the probability, p, that a number selected at random in the interval [144,169) is also in the interval [144,146.41) is p=252.41=2500241.
Note. Choosing x between 144 and 169 uniformly at random is not the same as choosing x uniformly at random between 12 and 13. This is what makes choice (C) wrong.