Problem: β£3βΟβ£=|3-\pi|=β£3βΟβ£=
Answer Choices:
A. 17\dfrac{1}{7}71β
B. 0.140.140.14
C. 3βΟ3-\pi3βΟ
D. 3+Ο3+\pi3+Ο
E. Οβ3\pi-3Οβ3
Solution:
Since 3βΟ<03-\pi<03βΟ<0, we have β£3βΟβ£=β(3βΟ)=Οβ3|3-\pi|=-(3-\pi)=\pi-3β£3βΟβ£=β(3βΟ)=Οβ3.