Problem:
If log2β(log2β(log2β(x)))=2, then how many digits are in the base-ten representation for x?
Answer Choices:
A. 5
B. 7
C. 9
D. 11
E. 13
Solution:
Since
log2β(log2β(log2β(x)))=2ββΊlog2β(log2β(x))=22=4,βΊlog2β(x)=24=16βΊx=216=26β
210β64β
1000,β
it follows that x has 5 base-ten digits.