Problem:
Triangle ABC is inscribed in a circle, and β B=β C=4β A. If B and C are adjacent vertices of a regular polygon of n sides inscribed in this circle, then n=
Answer Choices:
A. 5
B. 7
C. 9
D. 15
E. 18
Solution:
Since 180β=β A+β B+β C=β A+4β A+4β A, it follows that β A=20β. Therefore, BC=2β A=40β, which is 1/9 of 360β. Thus the polygon has 9 sides.
OR
If β C is partitioned into four angles congruent to β A, the four chords associated with the arcs subtended by these angles will be congruent to BC. These four chords plus four obtained analogously from β B, together with BC, form the n=9 sides of the inscribed regular polygon.
Note. In general, if β B=β C=kβ A, then n=2k+1.