Problem:
If x and y are non-zero real numbers such that
β£xβ£+y=3 and β£xβ£y+x3=0
then the integer nearest to xβy is
Answer Choices:
A. β3
B. β1
C. 2
D. 3
E. 5
Solution:
If x>0, then x+y=3 and y+x2=0. Eliminate y from these simultaneous equations to obtain x2βx+3=0, which has no real roots. If x<0, then we have βx+y=3 and βy+x2=0, which have a simultaneous real solution, so xβy=β3.
Note. One need not obtain the solution, (x,y)=(21β13ββ,27β13ββ), to find the answer.
OR
Sketch y=3ββ£xβ£ and y=β£xβ£βx3β={x2βx2βif x<0if x>0β.
Note that the graphs cross only on the half-line y=x+3,x<0. Therefore xβy=β3.