Problem:
In the sequence
β¦,a,b,c,d,0,1,1,2,3,5,8,β¦
each term is the sum of the two terms to its left. Find a.
Answer Choices:
A. β3
B. β1
C. 0
D. 1
E. 3
Solution:
Calculate d,c,b and a in that order from the definition of the sequence: 1=d+0, so d=1β; then 0=c+d, so c=β1β; next 1=d=b+c=bβ1, so b=2β; finally, β1=c=a+b=a+2, so a=β3β.
OR
Use the rule for generating terms of the sequence beginning with the two terms a,b:
a,b,a+b,a+2b,2a+3b,3a+5b,β¦
to see that 2a+3b=0 and 3a+5b=1. Solve simultaneously to find a=β3.