Problem: If 2+x=3\sqrt{2+\sqrt{x}}=32+x=3, then x=x=x=
Answer Choices:
A. 111
B. 7\sqrt{7}7
C. 777
D. 494949
E. 121121121
Solution:
Square both sides of the given equation to obtain 2+x=92+\sqrt{x}=92+x=9. Thus x=7\sqrt{x}=7x=7, and x=49x=49x=49, which satisfies the given equation.