Problem: (3!)!3!=\dfrac{(3!)!}{3!}=3!(3!)!=
Answer Choices:
A. 111
B. 222
C. 666
D. 404040
E. 120120120
Solution:
(3!)!3!=6!3!=6⋅5⋅4=120\dfrac{(3!)!}{3!}=\dfrac{6!}{3!}=6 \cdot 5 \cdot 4=1203!(3!)!=3!6!=6⋅5⋅4=120.
OR\textbf{OR} OR
(3!)!3!=6!6=5!=5⋅4⋅3⋅2=120\dfrac{(3!)!}{3!}=\dfrac{6!}{6}=5!=5 \cdot 4 \cdot 3 \cdot 2=1203!(3!)!=66!=5!=5⋅4⋅3⋅2=120.