Problem:
Let x1β=97, and for n>1 let xnβ=xnβ1βnβ. Calculate the product x1βx2ββ―x8β.
Solution:
For each n>1,xnβ1βxnβ=n. Using this fact for n=2,4,6 and 8, one obtains x1βx2ββ―x8β=(x1βx2β)(x3βx4β)(x5βx6β)(x7βx8β)=2β
4β
6β
8=384β.
Note: Except for the fact that it must be nonzero, the value of x, does not affect the solution.
The problems on this page are the property of the MAA's American Mathematics Competitions