Problem:
A circle with diameter  of length  is internally tangent at  to a circle of radius . Square  is constructed with  and  on the larger circle,  tangent at  to the smaller circle, and the smaller circle outside . The length of  can be written in the form , where  and  are integers. Find .

Solution:

Let be the center of the large circle. Note that , and are collinear since the circles are tangent. Let the line through , and intersect in and let . Then . Because is tangent at to the smaller circle, it follows that and that is a right angle. Hence, by the Pythagorean Theorem,
Solving for , we obtain . Since , we have , and .
The problems on this page are the property of the MAA's American Mathematics Competitions