Problem: The number
2420006+3520006\frac 2{\log_4{2000^6}} + \frac 3{\log_5{2000^6}} log4β200062β+log5β200063β
can be written as mn\frac mnnmβ where mmm and nnn are relatively prime positive integers. Find m+nm + nm+n.
Solution:
The problems on this page are the property of the MAA's American Mathematics Competitions