Problem:
Every positive integer k has a unique factorial base expansion (f1β,f2β,f3β,β¦,fmβ), meaning that k=1!β
f1β+2!β
f2β+3!β
f3β+β―+m!β
fmβ, where each fiβ is an integer, 0β€fiββ€i, and 0<fmβ. Given that (f1β,f2β,f3β,β¦,fjβ) is the factorial base expansion of 16!β32!+48!β64!+β―+1968!β1984!+2000!, find the value of f1ββf2β+f3ββf4β+β―+(β1)j+1fjβ.
Solution:
The problems on this page are the property of the MAA's American Mathematics Competitions