Problem:
In triangle ABC, angles A and B measure 60 degrees and 45 degrees, respectively. The bisector of angle A intersects BC at T, and AT=24. The area of the triangle ABC can be written in the form a+bcβ, where a,b, and c are positive integers, and c is not divisible by the square of any prime. Find a+b+c.
Solution:
Note that angles C and ATC each measure 75β, so AC=AT=24. Draw altitude CH of triangle ABC. Then triangle ACH is 30ββ60ββ90β and triangle BHC is 45ββ45ββ90β. Now AH=12 and BH=CH=123β. The area of triangle ABC is thus (1/2)123β(12+123β)=216+723β.