Problem:
Find the eighth term of the sequence 1440,1716,1848,β¦, whose terms are formed by multiplying the corresponding terms of two arithmetic sequences.
Solution:
The nth term of an arithmetic sequence has the form anβ=pn+q, so the product of corresponding terms of two arithmetic sequences is a quadratic expression, snβ=an2+bn+c. Letting n=0,1, and 2 produces the equations c=1440, a+b+c=1716, and 4a+2b+c=1848, whose common solution is a=β72, b=348, and c=1440. Thus the eighth term is s7β=β72β
72+348β
7+1440=348β. Note that snβ=β72n2+348n+1440=β12(2nβ15)(3n+8) can be used to generate pairs of arithmetic sequences with the desired products, such as {180,156,132,β¦} and {8,11,14,β¦}.
The problems on this page are the property of the MAA's American Mathematics Competitions