Problem:
Circles C1β and C2β are externally tangent, and they are both internally tangent to circle C3β. The radii of C1β and C2β are 4 and 10, respectively, and the centers of the three circles are collinear. A chord of C3β is also a common external tangent of C1β and C2β. Given that the length of the chord is mnβ/p, where m,n, and p are positive integers, m and p are relatively prime, and n is not divisible by the square of any prime, find m+n+p.
Solution:
The radius of C3β is 14. Let P1β,P2β, and P3β be the centers of C1β,C2β, and C3β, respectively. Draw perpendiculars from P1β,P2β, and P3β to the external tangent of C1β and C2β intersecting it at X,Y, and Z, respectively, so that P1βXβ,P2βYβ, P3βZβ are parallel, with P1βX=4 and P2βY=10. From P1β, draw a line parallel to XY intersecting P3βZβ and P2βYβ at Q and R, respectively. Note that P1βXYR is a rectangle and that right triangles P1βP2βR and P1βP3βQ are similar. Then P3βZ=P3βQ+QZ=(10/14)β 6+4=58/7. Because Z is the midpoint of the chord, the chord's length is 2142β(58/7)2β=8390β/7, and m+n+p=8+390+7=405β.