Problem:
Let ABCD be a square, and let E and F be points on AB and BC, respectively. The line through E parallel to BC and the line through F parallel to AB divide ABCD into two squares and two nonsquare rectangles. The sum of the areas of the two squares is 109β of the area of square ABCD. Find EBAEβ+AEEBβ.
Solution:
Let the sides of the two smaller squares have lengths x and y so that the square ABCD has side length x+y. It is given that x2+y2=109β(x+y)2. Then 10(x2+y2)=9(x2+y2)+18xy, and x2+y2=18xy. The requested sum is yxβ+xyβ=xyx2+y2β=18β.
The problems on this page are the property of the MAA's American Mathematics Competitions