Problem:
The expressions A=1Γ2+3Γ4+5Γ6+β―+37Γ38+39 and B= 1+2Γ3+4Γ5+β―+36Γ37+38Γ39 are obtained by writing multiplication and addition operators in an alternating pattern between successive integers. Find the positive difference between integers A and B.
Solution:
Observe
BβAβ=(1β39)+(3Γ2β1Γ2)+(5Γ4β3Γ4)+(7Γ6β5Γ6)+β―+(39Γ38β37Γ38)=β38+(2Γ2)+(2Γ4)+(2Γ6)+β―+(2Γ38)=β38+4Γ(1+2+3+β―+19)=β38+4Γ219β
20β=722β.β
The problems on this page are the property of the MAA's American Mathematics Competitions