Problem:
Triangle ABC has side lengths AB=9,BC=53β, and AC=12. Points A=P0β,P1β,P2β,β¦,P2450β=B are on segment AB with Pkβ between Pkβ1β and Pk+1β for k=1,2,β¦,2449, and points A=Q0β,Q1β,Q2β,β¦,Q2450β=C are on segment AC with Qkβ between Qkβ1β and Qk+1β for k=1,2,β¦,2449. Furthermore, each segment PkβQkββ,k=1,2,β¦,2449, is parallel to BC. The segments cut the triangle into 2450 regions, consisting of 2449 trapezoids and 1 triangle. Each of the 2450 regions has the same area. Find the number of segments PkβQkββ,k=1,2,β¦,2450, that have rational length.
Solution:
For 1β€kβ€2450,[APkβQkβ]=2450kβ[ABC], where the brackets denote area. Because the ratio of the areas of similar figures is the square of the ratio of the corresponding side lengths,
This last expression is rational if and only if k=6j2 for some positive integer j. Because kβ€2450, this is satisfied by j=1,2,3,β¦,20, giving 20β possible values of k.