Problem:
The diagram shows 28 lattice points, each one unit from its nearest neighbors. Segment AB meets segment CD at E. Find the length of segment AE.
Answer Choices:
A. 45β/3
B. 55β/3
C. 125β/7
D. 25β
E. 565β/9
Solution:
Extend DC to F. Triangle FAE and DBE are similar with ratio 5:4. Thus AE=5β AB/9,AB=32+62β=45β=35β, and AE=5(35β)/9=55β/3.
OR
Coordinatize the points so that A=(0,3),B=(6,0),C=(4,2), and D=(2,0). Then the line through A and B is given by x+2y=6, and the line through C and D is given by xβy=2. Solve these simultaneously to get E=(310β,34β). Hence AE=(310ββ0)2+(34ββ3)2β=9125ββ=355ββ.