Problem:
Find the value(s) of x such that 8xyβ12y+2xβ3=0 is true for all values of y.
Answer Choices:
A. 32β
B. 23β or β41β
C. β32β or β41β
D. 23β
E. β23β or β41β
Solution:
The given equation can be factored as
0=8xyβ12y+2xβ3=4y(2xβ3)+(2xβ3)=(4y+1)(2xβ3).
For this equation to be true for all values of y we must have 2xβ3=0, that is, x=3/2.
Answer: Dβ.
The problems on this page are the property of the MAA's American Mathematics Competitions