Problem:
Simplify
3x3x3xxββββ
Answer Choices:
A. xβ
B. 3x2β
C. 27x2β
D. 54xβ
E. 81x80β
Solution:
We have
3x3x3xxβββββ=(x(x(xβ
x21β)31β)31β)31β=(x(x(x23β)31β)31β)31β=(x(xβ
x21β)31β)31β=(x(x23β)31β)31β=(xβ
x21β)31β=(x23β)31β=x21β=xβ.β
Answer: Aβ.
The problems on this page are the property of the MAA's American Mathematics Competitions