Problem:
Which of the following is equivalent to
1βxxβ1βxββ
when x<0?
Answer Choices:
A. βx
B. x
C. 1
D. 2xββ
E. xβ1β
Solution:
We have
1βxxβ1βxββ=xxβx+1βxββ=x1βxββ=x2β=β£xβ£
When x<0, the given expression is equivalent to (A)βxβ.
The problems on this page are the property of the MAA's American Mathematics Competitions