Problem:
Suppose that the number a satisfies the equation 4=a+aβ1. What is the value of a4+aβ4?
Answer Choices:
A. 164
B. 172
C. 192
D. 194
E. 212
Solution:
Squaring each side of the equation 4=a+aβ1 gives
16=a2+2aβ
aβ1+(aβ1)2=a2+2+aβ2, so 14=a2+aβ2
Squaring again gives
196=a4+2a2β
aβ2+(aβ2)2=a4+2+aβ4, so (D)194β=a4+aβ4
The problems on this page are the property of the MAA's American Mathematics Competitions