Problem:
The fraction
(32007)2β(32005)2(32008)2β(32006)2β
simplifies to which of the following?
Answer Choices:
A. 1
B. 49β
C. 3
D. 29β
E. 9
Solution:
First note that
(32007)2β(32005)2(32008)2β(32006)2β=92007β9200592008β92006β
Factoring 92005 from each of the terms on the right side produces
92007β9200592008β92006β=92005β
92β92005β
192005β
93β92005β
91β=9200592005ββ
92β193β9β=9β
92β192β1β=(E)9β
The problems on this page are the property of the MAA's American Mathematics Competitions