Problem:
A quadratic equation ax2β2ax+b=0 has two real solutions. What is the average of the solutions?
Answer Choices:
A. 1
B. 2
C. abβ
D. a2bβ
E. 2aβbβ
Solution:
The quadratic formula implies that the two solutions are
x1β=2a2a+4a2β4abββ and x2β=2a2aβ4a2β4abββ
so the average is
21β(x1β+x2β)=21β(2a2aβ+2a2aβ)=(A)1β
OR
The sum of the solutions of a quadratic equation is the negative of the coefficient of the linear term divided by the coefficient of the quadratic term. In this case the sum of the solution is aβ(β2a)β=2. Hence the average of the solutions is (A)1β.