Problem:
Points A and C lie on a circle centered at O, each of BA and BC are tangent to the circle, and β³ABC is equilateral. The circle intersects BO at D. What is BOBDβ?
Answer Choices:
A. 32ββ
B. 21β
C. 33ββ
D. 22ββ
E. 23ββ
Solution:
Let the radius of the circle be r. Because β³BCO is a right triangle with a 30β angle at B, the hypotenuse BO is twice as long as OC, so BO=2r. It follows that BD=2rβr=r, and