Problem:
Suppose [a b] denotes the average of a and b, and {a b c} denotes the average of a,b, and c. What is {{1 1 0} [0 1] 0}?
Answer Choices:
A. 92β
B. 185β
C. 31β
D. 187β
E. 32β
Solution:
First note that {1 1 0}=32β and [0 1]=21β. Therefore
{{1 1 0} [0 1] 0}={32β 21β 0}=332β+21β+0β=(D)187ββ.
The problems on this page are the property of the MAA's American Mathematics Competitions