Problem:
What is 1+3+52+4+6ββ2+4+61+3+5β?
Answer Choices:
A. β1
B. 365β
C. 127β
D. 2049β
E. 343β
Solution:
Simplifying gives
1+3+52+4+6ββ2+4+61+3+5β=912ββ129β=34ββ43β=1216β9β=(C)127ββ.
The problems on this page are the property of the MAA's American Mathematics Competitions