Problem:
In rectangle ABCD,AB=1,BC=2, and points E,F, and G are midpoints of BC,CD, and AD, respectively. Point H is the midpoint of GE. What is the area of the shaded region?
Answer Choices:
A. 121β
B. 183ββ
C. 122ββ
D. 123ββ
E. 61β
Solution:
Let J be the intersection point of BF and HC. Then β³JHF is similar to β³JCB with ratio 1:2. The length of the altitude of β³JHF to HF plus the length of the altitude of β³JCB to CB is FC=21β. Thus β³JHF has altitude 61β and base 1, and its area is 121β. The shaded area is twice the area of β³JHF, or (E)61ββ.
OR
Place the figure on the coordinate plane with H at the origin. Then the equation of line DH is y=2x, and the equation of line AF is y=β4xβ1. Solving the equations simultaneously shows that the leftmost point of the shaded region has x-coordinate β61β. The kite therefore has diagonals 31β and 1, so its area is 21ββ 31ββ 1=(E)61ββ.