Problem:
For how many integers x is the number x4β51x2+50 negative?
Answer Choices:
A. 8
B. 10
C. 12
D. 14
E. 16
Solution:
Note that x4β51x2+50=(x2β50)(x2β1), so the roots of the polynomial are Β±1 and Β±50β. Arranged from least to greatest, these roots are approximately β7.1,β1,1,7.1. The polynomial takes negative values on the intervals (β7.1,β1) and (1,7.1), which include (C)12β integers: β7,β6,β5,β4,β3,β2,2,3,4,5,6,7.